Most of the time the ValueError happens while doing the programming in Python but did you ever face TypeError:
How to solve typeerror: str object is not callable?
TypeError:str object is not callable
In Python, the str() work is utilized for changing over a specific worth into a string.
It accepts an object as contention and converts it into a string.
As str is the name of a pre-characterized work in Python and is a held reserved keyword, it can’t be utilized elsewhere.
So in the event that you use str for naming a variable or a function, the Python compiler will throw an error.
Thus, you will experience a “TypeError ‘str’ object isn’t callable in Python” error.
Cause of TypeError: str object is not callable
This is a common error that happens when the user proclaims a variable with a similar name as the inbuilt function str() utilized in the code.
Python compiler treats str as a variable name, yet in our program, we are additionally utilizing in-built function str() as a function.
Because of this python compiler gets confused and creates an error: type error: ‘str’ object isn’t callable.
Str = “Hi This is” Str1 = “ Stechies” Print(str(str + str1))
Traceback (most recent call last):
File “str.py”, line 4, in <module>
Print(str(str + str1))
TypeError: ‘str’ object is not callable
In the above example, we are joining two string factors with the (+) operator, however, we proclaimed a variable named as “str” and on the following line, we are utilizing the str() function.
So python compiler takes “str” as a variable, not as a function because of which error “TypeError: ‘str’ object isn’t callable” happens.
Solve typeerror: str object is not callable?
To determine this mistake, you need to change the name of the variable whose name like the inbuilt function str() utilized in the code
Str2 = “Hi, he is” Str1 = “ Arman” Print(str(str2 + str1))
Hi, he is Arman
In the above example, we have just recently changed the name of variable “str” to “str2”
The “type error: ‘str’ object isn’t callable” error raise when you attempt to call a string as a capacity.
To settle this error, ensure you don’t utilize “str” as a variable name.
On the off chance that this doesn’t tackle the issue, check if you utilize the % operator to format strings.