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How to Declare Array Of Size n using Python

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I hope this article will help you to declare an array of size n in Python now we are talking about some very basic concepts of your regarding declaration. So, to Initialize them, you will have to add some other specific values, such as initializing them with 0.

Declare Array Of Size n using Python

n = 5 #length of list
list = [None] * n #populate list, length n with n entries "None"
print(list)
[None, None, None, None, None]

list.append(1) #append 1 to right side of list
list = list[-n:] #redefine list as the last n elements of list
print(list)
[None, None, None, None, 1]

list.append(1) #append 1 to right side of list
list = list[-n:] #redefine list as the last n elements of list
print(list)
[None, None, None, 1, 1]

list.append(1) #append 1 to right side of list
list = list[-n:] #redefine list as the last n elements of list
print(list)
[None, None, 1, 1, 1]

Python Initialize Array

array1 = [] #an empty array
array2 = list() #another empty arrat
array3 = ["1", "2", "3"] #array initialization with value
arrat4 = [x for x in range(1,11) #list comprehension

 

Declare Array Of Size n using Python

1. If you just want a sequence of numbers, the built-in function range is probably what you’re looking for.

For example, to create a list of numbers from 1 to 10, you would do this:

>>> list(range(1, 11))
[1, 2, 3, 4, 5, 6, 7, 8, 9 ,10]

2. If you want an array of a specific data type (e.g., floating-point), then you can use the built-in type constructor for that data type.

For example:

>>> import array
>>> array(‘d’, [1.0, 2.14, 3.14]) # double precision floating point

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